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\fbox{\parbox{\textwidth}{\Large\centering
    {\huge 98\% of people can't solve this 😂} \\
    $🍇 + 🍇 + 🍇 = 3$ \\
    $🍪 - 🍇 - 🍇 = 0$ \\
    $🥪 = \mathbb{Z} \quad 🍔 = 🥪/🍪🥪 \quad 🌭 = P^n(\mathbb{R})$ \\
    $H^*(🌭; 🍔) = \bigoplus_{k \in \mathbb{N}}H^k(🌭; 🍔)$ has a ring structure \\
    $🍕(-, B) : \mathcal{C} \to \mathbf{Set}$ is contravariant \\
    $🍕(A, B) = \{\phi : A \to B \mid \phi \textrm{ is a morphism}\}$ \\
    Given that 🍌 is the derived functor of 🍕 and the sequence \\
    $0 \to 🍌_{🍔}^{🍇}(H_{i - 🍇}(🌭; 🍔), 🥪) \to H^i(🌭; 🥪)
    \stackrel{h}{\to} 🍕_{🍔}(H_i(🌭; 🍔), 🥪) \to 0$ \\
    is exact, \\
    describe $H^*(🌭; 🍔)$ in terms of polynomial rings over 🍔.
}}
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